The two consecutive terms whose coefficients in the expanssion of (3+2x)94 are equal, are
37th, 38th
38th, 39th
47th, 48th
48th, 49th
Suppose coefficients of (r+1)th and (r+2)th terms in the expansion of (3 + 2x)94 are equal. Then 94Cr394−r2r=94Cr+1394−(r+1)2r+1⇒ 94!r!(94−r)!⋅(r+1)!(94−r−1)!94!=23⇒ r+194−r=23⇒3r+3=188−2r⇒ 5r=185⇒r=37