The two consecutive terms whose  coefficients in the expanssion of (3+2x)94 are equal, are

Suppose coefficients of (r+1)th and (r+2)th terms in the expansion of (3 + 2x)94 are equal. Then                            94Cr394−r2r=94Cr+1394−(r+1)2r+1⇒ 94!r!(94−r)!⋅(r+1)!(94−r−1)!94!=23⇒ r+194−r=23⇒3r+3=188−2r⇒ 5r=185⇒r=37