First slide

Theorems of probability

Question

Two dice are rolled and given that the sum is prime. The probability of getting sum more than 6 is

Easy

A

$\frac{7}{15}$
B

$\frac{8}{15}$
C

$\frac{1}{5}$
D

$\frac{2}{5}$

Solution

Sum={2,3,5,7,11} (prime)
Sum = more than 6 $\to$ 7,11

$P (E) = \frac{8}{15}$

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