First slide

Theorems of probability

Question

Two dice are rolled. The probability that the maximum of the two numbers is greater than 4 is

Easy

A

$\frac{8}{9}$
B

$\frac{1}{9}$
C

$\frac{4}{9}$
D

$\frac{5}{9}$

Solution

$n (S) = 36$
$\begin{matrix} E = {(1, 5) (1, 6) (2, 5) (2, 6) (3, 5) (3, 6) (4, 5) (4, 6) (5, 1) \\ (5, 2) (5, 3) (5, 4) (5, 5) (5, 6) (6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)} \end{matrix}$

$n (E) = 20$

$P (E) = \frac{20}{36} = \frac{5}{9}$

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