First slide

Theorems of probability

Question

$Two dice are rolled simultaneously. The probabilty that the numbers on them are different is$

Easy

A

$\frac{5}{6}$
B

$\frac{1}{4}$
C

$\frac{1}{2}$
D

$\frac{9}{13}$

Solution

$n (S) = 6^{2} = 36 (t o t a l n u m b e r o f p o s s i b l e o u t c o m e s w h e n t w o d i c e a r e r o l l e d s i m u l \tan e o u s l y)$
$Suppose that E be the event of getting two different numbers on dice n(E)= 6×5 =30$
$Therefore, the probability for the required event is P(E)= \frac{30}{36} = \frac{5}{6}$

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