Two dice are thrown at a time and the sum of the numbers on them is 9. The probability of getting a number 5 on any one of the dice is

P(59)=P(5∩9)P(9) P(AB)=P(A∩B)P(B)=24 A={(1,5) (2,5) (3,5) (4,5) (5,5) (6,5)(5.6)(5,4)(5,3)(5,2)(5,1)} B={(4,5) (5,4) (6,3) (3,6)} A∩B={(4,5) (5,4)}