Questions
Two equal circles with their centres on and axis will possess the radical axis in the following form
a
ax−by−a2+b24=0
b
2gx−2fy+g2−f2=0
c
g2x+f2y−g4−f4=0
d
2g2x+2f2y−g4−f4=0
detailed solution
Correct option is B
Let (x−a)2+(y−0)2=r2 and x2+(y−b)2=r2 be two equal circles with their centres on x and y axes respectively.Then, their radical axis is given by −2ax+a2+2by−b2=0⇒2ax−2by+b2−a2=0Clearly, is of the form 2gx−2fy+g2−f2=0Talk to our academic expert!
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