Q.
The two lines x=ay+b,z=cy+d and x=a'y+b',z=c'y+d' will be perpendicular, if and only if:
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a
aa'+bb'+cc'=0
b
(a+a')(b+b')+(c+c')=0
c
aa'+cc'+1=0
d
aa'+bb'+cc'+1=0
answer is C.
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Detailed Solution
Given lines can be written asx−ba=y−01=z−dc and x−b'a'=y−01=z−d'c'Required condition of perpendicularity is aa'+cc'+1=0
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