Two non-integer roots of 3x−12x+34−53x−12x+32+4=0 are

Let 3x−12x+32=tThen, given equation becomest2−5t+4=0⇒(t−1)(t−4)=0⇒t=1 or 4when, t=1,then 3x−12x+3=±1⇒ x=4,−25and when, t = 4then 3x−12x+3=±2⇒ x=−7,−5/7Thus, two non-integer roots of given equation are -25, -57,