Two numbers are selected at random from a set of first 120 natural numbers, then the probability that product of selected number is divisible by 3 is

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13357

199357

158357

160357

answer is B.

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Detailed Solution

{3,6,9,−−−,120}{1,2,4,5,−−−,119}P(A)=40C2+80C1×40C1120C2=199357

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