Questions
Two numbers b and c are chosen at random (with replacement from the numbers 1,2,3,4,5,6,7,8 and 9). The probability that for all is
detailed solution
Correct option is B
Here,x2+bx+c>0∀x∈R∴ D<0⇒ b2<4cvalue of b possible values of c1 1<4c ⇒c>14 ⇒{1,2,3,4,5,6,7,8,9}2 4<4c ⇒c>1 ⇒{2,3,4,5,6,7,8,9}3 9<4c ⇒c>94 ⇒{3,4,5,6,7,8,9}4 16<4c ⇒c>4 ⇒{5,6,7,8,9}5 25<4c ⇒c>625 ⇒{7,8,9}6 36<4c ⇒c>9 Impossible 7 impossible 8 impossible 9 impossibleNumber of favorable ca8e8 =9 + 8 + 7+6+3=32Total ways=9x9=81Required probability = 32/81Talk to our academic expert!
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