Questions
Two perpendicular tangents to the circle meet at Then the locus of has the equation
detailed solution
Correct option is A
Let the coordinates of P be (h, k). Then, the equation of the tangents drawn from P(h,k) to x2+y2=a2 is x2+y2−a2h2+k2−a2=hx+ky−a22 [Using SS' =T2 ]This equation represents a pair of perpendicular lines. Coeff. of x2+ Coeff. of y2=0 ⇒h2+k2−a2−h2+h2+k2−a2−k2=0 ⇒h2+k2=2a2 Hence, the locus of (h,k) is x2+y2=2a2.Talk to our academic expert!
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