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Q.

Two persons A, B have to speak at a function with 10 other persons. If the persons speak at random order, the probability that A speaks immediately before B is

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a

112

b

13

c

38

d

56

answer is A.

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Detailed Solution

n(S)=12!, (10+2=12) n(E)=11!×1→{AB} [AB−1 unit10−10 units] The probability that A speaks immediately before B is P(E)=11!12!=112
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Two persons A, B have to speak at a function with 10 other persons. If the persons speak at random order, the probability that A speaks immediately before B is