Cartesian plane

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Question

$Two sides of a rectangle are 3x+4y+5=0 and 4x-3y+15=0. If one of its vertices is (0,0), then the area of the rectangle is$

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Solution

$D i s \tan c e o f (0, 0) f r o m t h e g i v e n l i n e s i s a = \frac{|5|}{5} = 1 (\frac{|c|}{\sqrt{a^{2} + b^{2}}}) b = \frac{|15|}{5} = 3 a r e a o f r e c \tan g l e i s a b = 3 s q u n i t s$

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