The two successive terms in the expansion of (1 + x)24 whose coefficients are in the ratio 1:4 are
3rd and 4th
4th and 5th
5th and 6th
6th and 7t}r
Given expression is (1+x)24 Let two successive terms are (r + 1)th and (r + 2)thterms ⇒ Tr+1=24Crxr and Tr+2=24Cr+1xr+1
Now, ratio of coefficients = 1
⇒ 24Cr 24Cr+1=14⇒r+124−r=14⇒ 4r+4=24−r⇒r=4
.'. Required terms are 5th and 6th.