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An Intiative by Sri Chaitanya
a
1a2+1b2−1c2+1a12−1b12−1c12=0
b
1a2−1b2−1c2+1a12−1b12−1c12=0
c
1a2+1b2+1c2−1a12−1b12−1c12=0
d
1a2+1b2+1c2+1a12+1b12+1c12=0
answer is C.
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