Two tangents to the circle x2+y2=4 at the points A and B meet at P (- 4, 0). The area of the quadrilateral P AOB, where O is the origin, is

Area of quadrilateral PAOB= 2 ( Area of triangle OAP)=212×PA×POsin⁡θ=PA×PO×sin⁡θPA=42+02−4=23,PO=4 and, sin⁡θ=OAOP=24=12∴ Area of quadrilateral PAOB=23×4×12=43 sq. units.