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Q.

Two variable chords AB and BC of a circle x2+y2=a2 are such that AB = BC = a. M and N are the midpoints of AB and BC, respectively, such that the line joining MN intersects the circles at P and Q, where P is closer to AB and O is the center of the circle.∠OAB is The angle between the tangents at A and C isThe locus of the point of intersection of tangents at A and C is

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a

30°

b

60°

c

45°

d

15°

e

90°

f

120°

g

60°

h

150°

i

x2+y2=a2

j

x2+y2=2a2

k

x2+y2=4a2

l

x2+y2=8a2

answer is , , .

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Detailed Solution

From the figure, since ∆OAB is an equilateral triangle,∠OAB=60∘Let T be the point of intersection of tangents. Since ∠AOC=120∘,the angle between the tangents is 60°.The locus of the point of intersection of tangents at A and C is a circle whose center is O(0, 0) and radius isOT=a cosec ⁡π6=2aSo, the locus is x2+y2=4a2.
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