Two vertical poles AB = 15 m and CD = 10 m are standing apart on a horizontal ground with points A and C on the ground. If P is the point of intersection of BC and AD, then the height of P (in m) above the line AC is :

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10/3

20/3

answer is A.

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Detailed Solution

ΔCPQ~ΔCBAyx+y=h15ΔAPQ~ΔADCxx+y=h10(1)+(2)1=h15+h10h2+330=1⇒h=6

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