Q.
Two vertices of a triangle are (4,-3) and (-2,5). If the orthocenter of the triangle is at (1,2), then the third vertex is
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a
(-33,-26)
b
(33,26)
c
(26,33)
d
None of these
answer is B.
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Detailed Solution
Let the third vertex be (h,k) Now, the slope of AD is (k−2)/(h−1), the slope of BC is (5+3)/(−2−4)=−4/3,the slope of BE is (−3−2)/(4−1)=−5/3, and the slope of AC is (k−5)/(h+2). Since AD⊥BC, we have k−2h−1×−43=−1or 3h−5k+31=0_______(i)Again, since BE⊥AC,, we have −53×k−5h+2=−1or 3h−5k+31=0______(ii)On solving (i) and (ii), we get h=33, k=26. Hence, the third vertex is(33,26)
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