Two vertices of a triangle are (3, – 2) and (–2, 3) and its orthocenter is (–6, 1). Then the third vertex of this triangle can NOT lie on the line

Let m1=slope ofBH=1−(−2)−6−3=−13⇒Slope of AC=3 ∴Equation of AC is  y−3=3(x+2) or  3x−y+9=0       (1)Let m2 = slope of CH=1−3−6+2=12⇒Slope of AB  =-2∴Equation of AB is y+2=−2(x−3)or 2x+y−4=0                                (2)As A lies on (1) and (2), coordinates of A are (– 1, 6) and it does not lie on 5x+y=2