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A unit vector parallel to the intersection of the planes r→⋅(i^−j^+k^)=5 and r→⋅(2i^+j^−3k^)=4 is

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a

2i^+5j^−3k^38

b

2i^−5j^+3k^38

c

−2i^−5j^−3k^38

d

−2i^+5j^−3k^38

answer is C.

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Detailed Solution

a^=±n1→×n2→n1→×n→2=±2i^+5j^+3k^38 (where n→1 and n→2 are normal to the planes)

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