Q.

An urn A contains 8 black balls and 5 white balls. A second urn B contains 6 black and 7 white balls. The probability that a blind folded person in one draw shall obtain a white ball

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a

513

b

713

c

613

d

526

answer is C.

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Detailed Solution

P(W) =12(513)+12(713)             = 5+726  = 613
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An urn A contains 8 black balls and 5 white balls. A second urn B contains 6 black and 7 white balls. The probability that a blind folded person in one draw shall obtain a white ball