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$Use differential to approximate \sqrt{16.6}$

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4.4

1.3712

4.075

4.175

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detailed solution

Correct option is C

Take y=x, let x=16 and Δx=0.6Δy=(x+Δx)−x=16.6−16=16.6−4 or 16.6=Δy+4 Now dy is approximately equal to Δy and is given by dy=dydxΔx=12x(0.6)dy=1(216)(0.6)−18(0.6)=0.075 Thus, the approximate value of 16.6=4+0.075=4.075

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Use differential to approximate 16.6

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$Use differential to approximate \sqrt{16.6}$