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a
4.4
b
1.3712
c
4.075
d
4.175
answer is C.
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Detailed Solution
Take y=x, let x=16 and Δx=0.6Δy=(x+Δx)−x=16.6−16 =16.6−4 or 16.6=Δy+4 Now dy is approximately equal to Δy and is given by dy=dydxΔx= 12x(0.6)dy=1(216)(0.6)−18(0.6)=0.075