Use the function f(x)=x1/x,x>0, to determine the bigger of the two numbers eπ and πe.

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πe < eπ

πe > eπ

πe > 1

eπ < 1

answer is B.

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Detailed Solution

f(x)=x1/x,(x>0)⇒ f′(x)=x1/x(1−1nx)x2=0⇒x=e⇒ f'(x) ≤ 0, when x ≥e⇒ f(x) decreases when x ≥e And f′(x)>0, when 0e⇒ f(π)eπ

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