Using the fact that 0≤f(x)≤g(x),c<x<d
⇒∫cd f(x)dx≤∫cd g(x)dx we can conclude that
∫13 3+x3 lies in the interval
12,3
(2,30)
32,5
(4,230)
For x∈(1,3),2<3+x3<30 so
2∫13 dx<∫13 3+x3dx<30∫13 dx⇒4<∫13 3+x3dx<230