The value of 12+12+1100+12+2100+⋯+12+99100 is
We have,
12+n100<1 if n≤49
∴ 12+n100=0 if n≤49
Again 12+n100≥1 if n≥50
∴ 12+n100=1if50≤n≤99
The desired sum = 50