The value of (1−ω+ω2)⋅(1−ω2+ω4)⋅(1−ω4+ω8).....2n factors is equal to

First factor =−ω−ω=−2ω   Second factor =1−ω2+ω=−ω2−ω2=−2ω2 3rd factor, 5th factor, …….. are equal to the first factor,Which is −2ω .4th factor, 6the factor ….. are equal to the second factor.which is −2ω2 .∴ Required product =(−2ω)(−2ω2)(−2ω)(−2ω2)..........2n factors=(4ω3)(4ω3).........n factors=4.4......n factors =4n=(22)n=22n