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Questions  

The value of Arg[iln(aiba+ib)] ; where a  and b  are real numbers

a
0  or  π
b
π2
c
Not defined
d
None of these

detailed solution

Correct option is A

ln(a−iba+ib)=ln|a−iba+ib|+i[2nπ+arg(a−iba+ib)]                 =i[2nπ+arg(a−iba+ib)]  ∵|a−iba+ib|=1  ∴Arg[iln(a−iba+ib)]=Argi[−2nπ−arg(a−iba+ib)]=0  or  πAs 2nπ+arg(a−iba+ib)  is a real number.

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