A value of b for which the equations x2+bx-1=0 and x2+x+b=0 have one root in common, is
2
-i3
i5
-2
Let α be a common root of the given equations.
Then,
α2+bα−1=0 …(i)
α2+α+b=0 …(ii)
On subtracting, we get
(b−1)a=b+1>a=b+1b−1
Substituting the value of α in (i), we get
(b+1)2+b(b+1)(b−1)−(b−1)2=0
⇒ bb2−1+4h=0⇒ bb2+3=0⇒b=0,±i3