First slide
Theory of equations
Question

A value of b for which the equations x2+bx-1=0 and x2+x+b=0 have one root in common, is

Moderate
Solution

Let α be a common root of the given equations.

Then,

  α2+bα1=0                            …(i)

α2+α+b=0                               …(ii)

On subtracting, we get

(b1)a=b+1>a=b+1b1

Substituting the value of α in (i), we get

(b+1)2+b(b+1)(b1)(b1)2=0

   bb21+4h=0  bb2+3=0b=0,±i3

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