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The value of $2 C_{0} + \frac{2^{2}}{2} C_{1} + \frac{2^{3}}{3} C_{2} + \dots + \frac{2^{11}}{11} C_{10},$ is

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111211−1

111311−1

111113−1

111112−1

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detailed solution

Correct option is C

Given expression is equal to ∫02 C0+C1x+C2x2+⋯C10x10dx=∫02 (1+x)10dx=111311−1

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The value of 2C0+222C1+233C2+…+21111C10, is

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The value of $2 C_{0} + \frac{2^{2}}{2} C_{1} + \frac{2^{3}}{3} C_{2} + \dots + \frac{2^{11}}{11} C_{10},$ is