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The value of $^{50} C_{4} + \sum_{r = 1}^{6}^{56 - r} C_{3}$ is

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Correct option is B

50C4+∑r=16 56−rC3=50C4+ 55C3+54C3+…+50C3= 50C4+50C3+ 51C3+…+55C3= 51C4+51C3+ 52C3+…+55C3= 52C4+52C3+ 53C3+…+55C3=…..=56C4

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The value of 50C4+∑r=16 56−rC3 is

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The value of $^{50} C_{4} + \sum_{r = 1}^{6}^{56 - r} C_{3}$ is