The value of 50C4 +∑r=1656−rC3 is
55C4
55C3
56C3
56C4
50C4 +∑r=16 56−rC3 = 50c4+55c3+54c3+53c3+−−−+50c3
=C50,4+C50,3+C51,3+C52,3+.........+C55,3 ∵Cn,r+Cn,r−1=Cn+1,r=C51,4+C51,3+C52,3+......+C55,3=C52,4+C52,3+.........+C55,3..................=C56,4
=56c4