The value of 47C4+∑r=15 52−rC3 is equal to
47C6
52C5
52C4
None of these
47C4+∑r=15 52−rC3=47C4+51C3+50C3+49C3+48C3+47C3
=51C3+50C3+49C3+48C3+ 47C3+47C4=52C4