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The value of common ratio for which three successive terms of a GP are the sides of a triangle is

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a
r>0
b
r∈(0,1)
c
r∈5−12,5+12
d
None of these

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detailed solution

Correct option is C

Let  r be the  common  ratio. If r ≥ 1,  then  ar2 is the  greatest  term.    ∴    ar20     or=−1±52⇒r<−12(5+1) As     0


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