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Questions  

The value of cos2cos10.8,  is

a
0.48
b
0.96
c
0.6
d
0.28

detailed solution

Correct option is D

We have,          2cos−1⁡x=cos−1⁡2x2−1⇒ 2cos−1⁡0.8=cos−1⁡(2×0.64−1)=cos−1⁡(0.28)⇒ cos⁡2cos−1⁡0.8=cos⁡cos−1⁡0.28=0.28

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