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Q.

The value of cos−1⁡cos⁡−680∘,is

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a

π9

b

2π9

c

4π9

d

-π9

answer is B.

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Detailed Solution

cos−1⁡cos⁡−680∘=cos−1⁡cos⁡680∘=cos−1⁡cos⁡680×π180=cos−1⁡cos⁡34π9=cos−1⁡cos⁡4π−2π9=cos−1⁡cos⁡2π9=2π9
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