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The value of $\cos^{- 1} (\cos (- 680^{\circ}))$ ,is

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π9

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Correct option is B

cos−1⁡cos⁡−680∘=cos−1⁡cos⁡680∘=cos−1⁡cos⁡680×π180=cos−1⁡cos⁡34π9=cos−1⁡cos⁡4π−2π9=cos−1⁡cos⁡2π9=2π9

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The value of cos−1⁡cos⁡−680∘,is

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The value of $\cos^{- 1} (\cos (- 680^{\circ}))$ ,is