The value of cos12∘cos24∘cos36∘cos48∘cos72∘cos84∘, is
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a
1/64
b
1/32
c
1/16
d
1/128
answer is A.
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Detailed Solution
We have,cos12∘cos24∘cos36∘cos48∘cos72∘cos84∘=−cos12∘cos24∘cos48∘cos96∘cos36∘cos72∘ =−sin24×12∘24sin12∘×cos36∘sin18∘=−sin192∘16sin12∘×5+14×5−14=116×14=164