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Q.

The value of cos3π8·cos3π8+sin3π8·sin3π8 is:

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a

14

b

12

c

12

d

122

answer is D.

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Detailed Solution

=cos3π84cos3π8-3cosπ8+sin3π83sinπ8-4sin3π8=4cos6π8-4sin6π8-3cos4π8+3sin4π8=4cos2π8-sin2π8sin4π8+cos4π8+sin2π8cos2π8-3cos2π8-sin2π8=cosπ441-sin2π8cos2π8-3=121-12=∣122
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