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$The value of \cos^{3} (\frac{π}{8}) \cdot \cos (\frac{3 π}{8}) + \sin^{3} (\frac{π}{8}) \cdot \sin (\frac{3 π}{8}) is:$

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detailed solution

Correct option is D

=cos3π84cos3π8-3cosπ8+sin3π83sinπ8-4sin3π8=4cos6π8-4sin6π8-3cos4π8+3sin4π8=4cos2π8-sin2π8sin4π8+cos4π8+sin2π8cos2π8-3cos2π8-sin2π8=cosπ441-sin2π8cos2π8-3=121-12=∣122

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The value of cos3π8·cos3π8+sin3π8·sin3π8 is:

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$The value of \cos^{3} (\frac{π}{8}) \cdot \cos (\frac{3 π}{8}) + \sin^{3} (\frac{π}{8}) \cdot \sin (\frac{3 π}{8}) is:$