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The value of cos (2 cos^–1x + sin^–1x) at x = $\frac{1}{5}$ is

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Correct option is B

cos (2 cos–1x + sin–1x)= cos (cos–1x + cos–1x + sin–1x)=cos⁡π2+cos−1⁡x=−sin⁡cos−1⁡x=−sin⁡sin−1⁡1−x2=−1−x2=−1−125=−265

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The value of cos (2 cos–1x + sin–1x) at x = 15 is

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The value of cos (2 cos^–1x + sin^–1x) at x = $\frac{1}{5}$ is