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The value of π/2π/2costsin(2tπ/4)dt is

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a
−1/3
b
1/3
c
2/3
d
-2/3

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detailed solution

Correct option is D

∫−π/2π/2 cos⁡tsin⁡2t−π4dt=12∫−π/2π/2 cos⁡t(sin⁡2t−cos⁡2t)dt=−12∫−π/2π/2 cos⁡tcos⁡2tdt=−22∫0π/2 (cos⁡3t+cos⁡t)dt=−12−13+1=−12⋅23=−23


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