The value of ∫−ππ cos2x1+axdx,a>0 is
π/2
aπ
π
2π
Let I=∫−ππ cos2x1+axdx
Put x=−θ to obtain
I=∫π−π cos2θ1+a−θ(−1)dθ=∫−ππ axcos2x1+axdx
Adding (1) and (2), we get
2I=∫−ππ cos2xdx=2∫0π cos2xdx=π⇒I=π/2