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The value of 0π/21+2cosx(2+cosx)2dx  is

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a
-1/2
b
2
c
1/2
d
none of these

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detailed solution

Correct option is C

∫0π/2 1+2cos⁡x(2+cos⁡x)2dx=∫0π/2 2(cos⁡x+2)−3(2+cos⁡x)2dx=4∫01 dt3+t2−6∫01 1+t23+t22dt (t=tan⁡x/2)=−2∫01 dt3+t2+12∫01 dt3+t22=−2∫01 dt3+t2+1212.3tt2+301+12.3∫01 dt3+t2=12.


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