First slide
Evaluation of definite integrals
Question

The value of π2π2cos2x1+3xdx

Moderate
Solution

I=π2π2cos2x1+3xdx    =π2π2cos2x1+3xdx  since -aaf(x)dx =-aaf(-x)dxI=π2π23xcos2x3x+1dx  2I=  -π2π2cos2x1+3x3x+1dx=π2π2cos2x  dx=20π2cos2x  dx     ( since cos2x is even function)=2×12×π2I=π4

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