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Questions  

Value of 3+cot80cot20cot80+cot20 is equal to

a
Cot 15o
b
Tan 50o
c
Cot 50o
d
Cot 20°

detailed solution

Correct option is B

3+cos⁡80∘cos⁡20∘sin⁡80∘sin⁡20∘cos⁡80∘sin⁡80∘+cos⁡20∘sin⁡20∘=2sin⁡80∘sin⁡20∘+cos⁡80∘cos⁡20∘+sin⁡80∘sin⁡20∘sin⁡20∘cos⁡80∘+cos⁡20∘sin⁡80∘=−cos⁡100∘+cos⁡60∘+cos⁡60∘sin⁡100∘=1−cos⁡100∘sin⁡100∘=tan⁡50∘

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