First slide
Multiple and sub- multiple Angles
Question

The value of cotθtanθ2tan2θ4tan4θ8cot8θ is 

Moderate
Solution

We know that

 cotαtanα=2cot2αcotθtanθ2tan2θ4tan4θ8cot8θ=2cot2θ2tan2θ4tan4θ8cot8θ=2(2cot4θ)4tan4θ8cot8θ=4cot4θ4tan4θ8cot8θ=4(cot4θtan40)8cot8θ=4×2cot8θ8cot8θ=0

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