First slide
Evaluation of definite integrals
Question

The value of π/4π/3dxsinx+tanx is

Moderate
Solution

I=π/4π/3cosxsinx(cosx+1)dx

=π/4π/3cosxsinx1-cos2x(1+cosx)dx

Put cosx=t so that

I=1/21/2tdt(1+t)2(1-t)

=1/21/21411+t+11-t-12(1+t)2dt

=14log1+t1t+12(1+t)1/21/2=14log2+12123+12+213

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