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The value dxx4+5x2+4 IS

 

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a
(1/3)tan−1⁡x−(1/2)tan−1⁡(x/2)+C
b
3tan−1⁡(x/3)+2tan−1⁡(x/2)+C
c
(1/3)tan−1⁡x+(1/6)tan−1⁡(x/2)+C
d
(1/3)tan−1⁡x−(1/6)tan−1⁡(x/2)+C

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detailed solution

Correct option is D

I=∫dxx4+5x2+4=∫dxx2+1x2+4=∫131x2+1−1x2+4dxTherefore, I=13tan−1⁡x−16tan−1⁡x2+C.


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