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The value of dx(x1)3(x+2)54 is 

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a
3(x−1)1/4−(5/3)(x+2)3/4+C
b
4(x−14)−5(x+2)54+C
c
43x−1x+2+C4
d
none of these

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detailed solution

Correct option is C

I=∫dx4(x−1)3(x+2)5=∫x−1x+2−3/41(x+2)2dxNow put  x−1x+2=t to obtain I=13∫t−3/4dt=43t1/4+C


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