The value of ∫dx4x−3−x2 is equal to
sin−1(x−1)+C
log(x−2)+4x−3−x2
log(x−1)+4x−3−x2+C
sin−1(x−2)+C
4x−3−x2=−x2−4x+3
=−(x−2)2−1=1−(x−2)2
So, ∫dx4x−3−x2=∫dx1−(x−2)2=sin−1(x−2)+C