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The value of is equal to
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a
sin−1(x−1)+C
b
log(x−2)+4x−3−x2
c
log(x−1)+4x−3−x2+C
d
sin−1(x−2)+C
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Correct option is D
4x−3−x2=−x2−4x+3=−(x−2)2−1=1−(x−2)2So, ∫dx4x−3−x2=∫dx1−(x−2)2=sin−1(x−2)+CSimilar Questions
is equal to
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